If the Boolean expression (p⊕q)∧(∼p⊙q) is equivalent to p∧q, where ⊕,⊙∈{∧,∨}, then the ordered pair (⊕,⊙) is :If the Boolean expression $(p\oplus q)\land(\sim p\odot q)$ is equivalent to $p\land q$, where $\oplus,\odot\in\{\land,\lor\}$, then the ordered pair $(\oplus,\odot)$ is : (1) $(\land,\lor)$ (2) $(\lor,\lor)$ (3) $(\land,\land)$ (4) $(\lor,\land)$