Question

For the circuit given below, the Kirchoff's loop rule for the loop BCDEB is given by the equation

(1) –i₂R₂ + E₂ + E₃ + i₃R₁ = 0 

(2) –i₂R₂ + E₂ – E₃ + i₃R₁ = 0 

(3) i₂R₂ + E₂ – E₃ – i₃R₁ = 0 

(4) i₂R₂ + E₂ + E₃ + i₃R₁ = 0

Comments

here the i3 is in the same direction of current then only it will work out so pls respond to my conclusion

Answer 1

Ans: (3) i₂R₂ + E₂ – E₃ – i₃R₁ = 0

Sol. In a loop BCDEB by KVL 

V_B – i₂R₂ – E₂ + E₃ + i₃R₁ = V_B 

i₂R₂ + E₂ – E₃ – i₃R₁ = 0