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For the circuit given below, the Kirchoff's loop rule for the loop BCDEB is given by the equation

(1) –i2R2 + E2 + E3 + i3R1 = 0 

(2) –i2R2 + E2 – E3 + i3R1 = 0 

(3) i2R2 + E2 – E3 – i3R1 = 0 

(4) i2R2 + E2 + E3 + i3R1 = 0

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here the i3 is in the same direction of current then only it will work out so pls respond to my conclusion

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Ans: (3) i2R2 + E2 – E3 – i3R1 = 0

Sol. In a loop BCDEB by KVL 

VB – i2R2 – E2 + E3 + i3R1 = VB 

i2R2 + E2 – E3 – i3R1 = 0

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