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When the switch S, in the circuit shown, is closed, then the value of current i will be :

(1) 3 A 

(2) 5 A 

(3) 4 A 

(4) 2 A

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Ans: (2) 5 A 

Sol:

Let voltage at C = xv

KCL : i1 + i2 = i 

${20-x\over2}+{10-x\over4}={x-0\over2}$

$\implies x=10$

and i = 5 amp.

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