When the switch S, in the circuit shown, is closed, then the value of current i will be :
(1) 3 A
(2) 5 A
(3) 4 A
(4) 2 A
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Ans: (2) 5 A
Sol:
Let voltage at C = xv
KCL : i1 + i2 = i
${20-x\over2}+{10-x\over4}={x-0\over2}$
$\implies x=10$
and i = 5 amp.
For the circuit shown in the figure, the current I will be (1) 0.5 A (2) 0.75 A (3) 1 A (4) 1.5 A
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