menu search
brightness_auto
Feel free to answer or ask any questions.
If you are new here please see how to use or FAQ.
more_vert

A small block starts slipping down from a point B on an inclined plane AB, which is making an angle $\theta$ with the horizontal section BC is smooth and the remaining section CA is rough with a coefficient of friction $\mu$. It is found that the block comes to rest as it reaches the bottom (point A) of the inclined plane. If BC = 2AC, the coefficient of friction is given by $\mu=k\tan\theta$. The value of k is .........

Numerical Value Type

more_vert
Hard question for me

1 Answer

more_vert
 
verified
Best answer

Ans. 3

Sol. Let $AC=l$ 

$\therefore BC=2l$ 

$\therefore AB=3l$

Apply work-Energy theorem

$W_f+W_{mg}=\Delta KE$

$mg(3l)\sin\theta-\mu mg\cos\theta(l)=0+0$

$\mu mg\cos\theta l=3mgl\sin\theta$

$\mu=3\tan\theta=k\tan\theta$

$\therefore k=3$

thumb_up_off_alt 1 like thumb_down_off_alt 0 dislike
more_vert
You make it very easy

Welcome to Jee Neet QnA, where you can ask questions and receive answers from other members of the community.


Join our Telegram group for live discussion.

Telegram Group

Subscribe our YouTube channel for video solutions with explanation.

YouTube Channel

Download Jee Neet QnA Books in PDF for offline learning.

Jee Neet QnA Books

1.2k questions

842 answers

384 comments

92 users

...