menu search
brightness_auto
Feel free to answer or ask any questions.
If you are new here please see how to use or FAQ.
more_vert

A charged particle (mass m and charge q) moves along X axis with velocity V0. When it passes through the origin it enters a region having uniform electric field $\vec{E}=-E\hat{j}$ which extends upto x = d. Equation of path of electron in the region x > d is :

(1) $y={qEd\over mV_0^2}x$

(2) $y={qEd\over mV_0^2}(x-d)$

(3) $y={qEd\over mV_0^2}\left({d\over2}-x\right)$

(4) $y={qEd^2\over mV_0^2}x$

more_vert
Electrostatics, electric charges and Fields

2 Answers

more_vert
 
verified
Best answer

Ans. (3) $y={qEd\over mV_0^2}\left({d\over2}-x\right)$

Sol.

x > d path is straight line

${-y-{1\over2}at^2\over x-d}={at\over V_0}$

${-y-{1\over2}at^2\over at}={x-d\over V_0}$

${-y\over at}-{1\over2}{d\over V_0}={x\over V_0}-{d\over V_0}$

${-myV_0\over qEd}={x\over V_0}-{d\over2V_0}$

$y={-qEd\over mV_0}\left({x\over V_0}-{d\over2V_0}\right)$

$y={qEd\over mV_0^2}\left({d\over2}-x\right)$

thumb_up_off_alt 1 like thumb_down_off_alt 0 dislike
more_vert
Solve yourself
thumb_up_off_alt 0 like thumb_down_off_alt 2 dislike

Welcome to Jee Neet QnA, where you can ask questions and receive answers from other members of the community.


Join our Telegram group for live discussion.

Telegram Group

Subscribe our YouTube channel for video solutions with explanation.

YouTube Channel

Download Jee Neet QnA Books in PDF for offline learning.

Jee Neet QnA Books

1.2k questions

844 answers

385 comments

139 users

...