Question

Specific volume of cylindrical virus particle is 6.02 × 10^-2 cc/g whose radius and length are 7 Å and 10 Å respectively. If N_A = 6.02 × 10²³, find molecular weight of virus.

(a) 15.4 kg/mol

(b) 1.54 × 10⁴ kg/mol

(c) 3.08 × 10⁴ kg/mol

(d) 3.08 × 10³ kg/mol

Answer 1

Ans: (a) 1.54 kg/mol