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Specific volume of cylindrical virus particle is 6.02 × 10-2 cc/g whose radius and length are 7 Å and 10 Å respectively. If NA = 6.02 × 1023, find molecular weight of virus.

(a) 15.4 kg/mol

(b) 1.54 × 104 kg/mol

(c) 3.08 × 104 kg/mol

(d) 3.08 × 103 kg/mol

1 Answer

Best answer

Ans: (a) 1.54 kg/mol

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