Percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt. = 78.4) then minimum molecular weight of peroxidase anhydrous enzyme is
(a) 1.568 × 104
(b) 1.568 × 103
(c) 15.68
(d) 2.136 × 104
Ans. (a) 1.568 × 104
Sol. Given -
0.5% of Se
that is there is 0.5g of Se in 100g of peroxidase anhydrous enzyme
to find the minimum molecular weight of enzyme we consider the minimum amount of Selenium in the enzyme to be is one atom (its atomic mass)
let the minimum molecular wt of enzyme be x
mass of Se | mass of enzume |
---|---|
0.5g | 100g |
78.4g | xg |
now, for 0.5g of Se -> 100g of enzyme
for 1g of Se -> 100 / 0.5 = 200g of enzyme
thus for 78.4g of Se -> (200 x 78.4)g = 15680g of enzyme
MINIMUM MOLECULAR WEIGHT OF PEROXIDASE ANHYDROUS ENZYME = 15680g = 1.568 x 104 g