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An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be

(a) CHO

(b) CH4O

(c) CH3O

(d) CH2O

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Best answer

Ans. (d) CH2O

Sol.

The mass % of - C = 38.71

                             H = 9.67

                             O = 100-(38.71+9.67) = 51.62

 

to find empirical formula - 

Elements% in compoundatomic nono of molessimple ratio simple ratio 
C                                   38.71            12 38.71/12 = 3.223.22/3.22 = 1        1
H                                    9.67             19.67/1 = 9.679.67/3.22 = 3        3
0                                   51.62            1651.62/16 = 3.223.22/3.22 = 1        1

empirical formula = CH2O

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