Question

The number of atoms in 0.1 mol of a triatomic gas is (N_A = 6.02 × 10²³ mol^-1)

(a) 6.026 × 10²²

(b) 1.806 × 10²³

(c) 3.600 × 10²³

(d) 1.800 × 10²²

Answer 1

Answer - (2) 1.806 × 10²³

Solution - 

no. of atoms in a compound = no. of moles × no. of atoms × N_A 

    = 0.1 × 3 × 6.023 × 10²³

    = 1.8069 × 10²³ 

    = 1.806 × 10²³  atoms

Comments

thankyou for providing soloution