The number of atoms in 0.1 mol of a triatomic gas is (NA = 6.02 × 1023 mol-1)
(a) 6.026 × 1022
(b) 1.806 × 1023
(c) 3.600 × 1023
(d) 1.800 × 1022
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Answer - (2) 1.806 × 1023
Solution -
no. of atoms in a compound = no. of moles × no. of atoms × NA
= 0.1 × 3 × 6.023 × 1023
= 1.8069 × 1023
= 1.806 × 1023 atoms
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