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The number of atoms in 0.1 mol of a triatomic gas is (NA = 6.02 × 1023 mol-1)

(a) 6.026 × 1022

(b) 1.806 × 1023

(c) 3.600 × 1023

(d) 1.800 × 1022

1 Answer

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Answer - (2) 1.806 × 1023

Solution - 

no. of atoms in a compound = no. of moles × no. of atoms × N

    = 0.1 × 3 × 6.023 × 1023

    = 1.8069 × 1023 

    = 1.806 × 1023  atoms

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