# In the electrochemical cell : Zn|ZnSO4(0.01 M)||CuSO4(1.0 M)|Cu, the emf of this Daniell cell is E1.

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In the electrochemical cell : $\require{mhchem}\ce{Zn|ZnSO4}(\text{0.01 M})||\ce{CuSO4}(\text{1.0 M})|\ce{Cu}$, the emf of this Daniell cell is $E_1$. When the concentration of $\ce{ZnSO4}$ is changed to $\text{1.0 M}$ and that of $\ce{CuSO4}$ changed to $\text{0.01 M}$, the emf changes to $E_2$. From the followings, which one is the relationship between $E_1$ and $E_2$? (Given, $\text{RT/F = 0.059}$)

(a) $E_1 < E_2$

(c) $E_2 = 0^1 E_1$

(b) $E_1 > E_2$

(d) $E_1 = E_2$