6.02 × 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is
(a) 0.001 M
(b) 0.1 M
(c) 0.02 M
(d) 0.01 M
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Ans. (d) 0.01 M
Sol. no of moles = no of molecules / NA
n = 6.02 x 1020 / 6.02 x 1023
n = 10-3
Molarity = no of moles / volume of solution(L)
M= 0.001/100 x 1000
M = 0.01M
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