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6.02 × 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is

(a) 0.001 M

(b) 0.1 M

(c) 0.02 M

(d) 0.01 M

1 Answer

Best answer

Ans. (d) 0.01 M

Sol. no of moles = no of molecules / NA

n = 6.02 x 1020 / 6.02 x 1023 

n = 10-3

Molarity = no of moles / volume of solution(L)

M= 0.001/100 x 1000 

M = 0.01M

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