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Equal masses of H2, O2 and methane have been taken in a container of volume V at temperature 27 °C in identical conditions. The ratio of the volumes of gases H2 : O2 : methane would be

(a) 8 : 16 : 1

(b) 16 : 8 : 1

(c) 16 : 1 : 2

(d) 8 : 1 : 2

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Answer - (c) 16 : 1 : 2

 

Solution - 

Lets assume that there are 100g of each 

then the no.of moles = i) Hydrogen = H2 = 100/2 

                                    ii) Oxygen = O2 = 100/ 32 

                                    iii) Methane = CH4 = 100/16 

The ratio = 100/2 : 100/32 : 100/16 

               = 1/1 : 1/16 : 1/8 }→ x 16 (multiply all by 16)

               =  16 : 1 : 2

Thus Answer = (c) 16 : 1 : 2

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