# If the Boolean expression (p⊕q)∧(∼p⊙q) is equivalent to p∧q, where ⊕,⊙∈{∧,∨}, then the ordered pair (⊕,⊙) is :

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If the Boolean expression $(p\oplus q)\land(\sim p\odot q)$ is equivalent to $p\land q$, where $\oplus,\odot\in\{\land,\lor\}$, then the ordered pair $(\oplus,\odot)$ is :

(1) $(\land,\lor)$

(2) $(\lor,\lor)$

(3) $(\land,\land)$

(4) $(\lor,\land)$