menu search
brightness_auto
Feel free to answer or ask any questions.
If you are new here please see how to use or FAQ.
more_vert

0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a a container of volume 10 m3 at 1000 K. given R is the gas constant in JK–1 mol–1m, x is : 

(1) $2R\over4+12$ 

(2) $2R\over4–R$ 

(3) $4–R\over2R$ 

(4) $4+R\over2R$

more_vert
States of matter

1 Answer

more_vert
 
verified
Best answer
Ans:(3).4-R/2R

Explanation: nt=0.5+x, P=200Pa, V=10m³, T=1000K, R= gas constant. PV = nRT

0.5+x = 200×10/R×1000 = 2/R

x = 2/R-0.5 = 4-R/2R.
thumb_up_off_alt 1 like thumb_down_off_alt 0 dislike

Welcome to Jee Neet QnA, where you can ask questions and receive answers from other members of the community.


Join our Telegram group for live discussion.

Telegram Group

Subscribe our YouTube channel for video solutions with explanation.

YouTube Channel

Download Jee Neet QnA Books in PDF for offline learning.

Jee Neet QnA Books

1.2k questions

842 answers

383 comments

89 users

...