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0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a a container of volume 10 m3 at 1000 K. given R is the gas constant in JK–1 mol–1m, x is : 

(1) $2R\over4+12$ 

(2) $2R\over4–R$ 

(3) $4–R\over2R$ 

(4) $4+R\over2R$

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Ans:(3).4-R/2R

Explanation: nt=0.5+x, P=200Pa, V=10m³, T=1000K, R= gas constant. PV = nRT

0.5+x = 200×10/R×1000 = 2/R

x = 2/R-0.5 = 4-R/2R.
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