Question

0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a a container of volume 10 m³ at 1000 K. given R is the gas constant in JK^–1 mol^–1m, x is : 

(1) $2R\over4+12$ 

(2) $2R\over4–R$ 

(3) $4–R\over2R$ 

(4) $4+R\over2R$

Comments

States of matter

Answer 1

Ans:(3).4-R/2R

Explanation: nt=0.5+x, P=200Pa, V=10m³, T=1000K, R= gas constant. PV = nRT

0.5+x = 200×10/R×1000 = 2/R

x = 2/R-0.5 = 4-R/2R.