Feel free to answer or ask any questions.
If you are new to this type of forum, see How To Use.
menu search brightness_auto
more_vert

Drift speed of electrons, when 1.5 A of current flows in a copper wire of cross section 5 mm2, is v. If the electron density in copper is 9 × 1028 /m3 the value of v in mm/s is close to (Take charge of electron to be = 1.6 × 10–19C)

(1) 0.2 

(2) 3 

(3) 2 

(4) 0.02

thumb_up_off_alt 2 like thumb_down_off_alt 0 dislike

1 Answer

more_vert
 
done_all
Best answer

Ans: (4) 0.02

Sol: $I = neAv_d$

$\implies v_d={I\over neA}$

$={1.5\over9\times10^{28}\times1.6\times10^{-19}\times5\times10^{-6}}$

$=0.02\text{ m/s}$

thumb_up_off_alt 0 like thumb_down_off_alt 0 dislike

Related questions

thumb_up_off_alt 1 like thumb_down_off_alt 0 dislike
1 answer
Most active Members
this week:
  1. Vishal Kumar1 points

929 questions

562 answers

297 comments

29 users

...