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Surface of certain metal is first illuminated with light of wavelength $\lambda_1$= 350 nm and then, by light of wavelength $\lambda_2$= 540 nm. It is found that the maximum speed of the photo electrons in the two cases differ by a factor of 2. The work function of the metal (in eV) is close to : (Energjr of photon = ${1240\over\lambda(\text{in nm})}$eV )

(1) 1.8

(2) 1.4

(3) 2.5

(4) 5.6

1 Answer

Best answer

Ans: (1) 1.8

Sol: ${hc\over\lambda_1}=\phi+{1\over2}m(2v)^2$







$=1.8\text{ eV}$

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