menu search
brightness_auto
Feel free to answer or ask any questions.
If you are new here please see how to use or FAQ.
more_vert
A sample of radioactive material A, that has an activity of 10 mCi(1 Ci = 3.7 × 1010 decays/s), has twice the number of nuclei as another sample of a different radioactive material B which has an activity of 20 mCi. The correct choices for half-lives of A and B would then be respectively :

(1) 20 days and 5 days

(2) 20 days and 10 days

(3) 5 days and 10 days

(4) 10 days and 40 days

1 Answer

more_vert
 
verified
Best answer

Ans: (1) 20 days and 5 days

Sol: Activity A = $\lambda$N 

For A     10 = (2N0)$\lambda$A 

For B     20 = N0$\lambda$B 

$\therefore \lambda_B=4\lambda_A\implies(T_{1/2})_A =4(T_{1/2})_B$

thumb_up_off_alt 1 like thumb_down_off_alt 0 dislike

Welcome to Jee Neet QnA, where you can ask questions and receive answers from other members of the community.


Join our Telegram group for live discussion.

Telegram Group

Subscribe our YouTube channel for video solutions with explanation.

YouTube Channel

Download Jee Neet QnA Books in PDF for offline learning.

Jee Neet QnA Books

1.2k questions

841 answers

383 comments

87 users

...