In the given nuclear reaction, the element X is :
${}_{11}^{22}Na \to X+e^++v$
(1) ${}_{10}^{22}Ne$
(2) ${}_{12}^{22}Mg$
(3) ${}_{11}^{23}Na$
(4) ${}_{10}^{23}Ne$
${}_{11}^{22}Na \to X+e^++v$
(1) ${}_{10}^{22}Ne$
(2) ${}_{12}^{22}Mg$
(3) ${}_{11}^{23}Na$
(4) ${}_{10}^{23}Ne$