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What is the fraction of the solute in a 1.00m aqueous solution
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Answer:

Correct option is (C) 0.0177

Solution:

1.00 m aqueous solution means 1 mole of solute in 1 kg of water.

1 kg of water corresponds to ${1000\over18}=55.56$ moles.

The mole fraction of solute is ${1\over1+55.56}=0.0177$.

Hence, the correct option is (C) 0.0177

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