Time period of simple pendulum at a planet is 2 sec. Length of simple pendulum is 2 meter. Find the value of g at that planet (in m/s2)
(1) 2$\pi$2
(2) 9.8 m/s2
(3) 10 m/s2
(4) $\pi^2\over2$m/s2
Ans. (1) 2$\pi$2
Sol. $T=2\pi\sqrt{\ell\over g_\text{planet}}$
$\implies2=2\pi\sqrt{2\over g_\text{planet}}$
$\implies{1\over\pi^2}={2\over g_\text{planet}}$
$\implies$ gplanet = 2$\pi$2 m/sec2
929 questions
555 answers
292 comments
32 users