Statement-1: Rotational KE of a gas molecule follows Maxwell's speed distribution curve.
Statement-2: Rotational KE & translational KE of a diatomic gas molecule is same.
(1) 1-true 2-false
(2) 1-false 2-true
(3) 1-false 2-false
(4) 1-true 2-true
Ans. (3) 1-false 2-false
Sol. Maxwell's Boltzmann distribution curve is always drawn for no. of molecules (N) vs velocity of molecules. so statement-1 is false.
T.K.E. of diatomic molecule = $3\over2$KT
R.K.E. of diatomic molecule = $2\over2$KT
Statement-2 is false.