menu search
brightness_auto
Feel free to answer or ask any questions.
If you are new here please see how to use or FAQ.
more_vert

If the current flowing in a coil is reduced to half of its original value, the relaticn between the new energy (E2) and the original energy (E1) stored in the coil will be

(A) E2 = E1

(B) E2 = 2E1

(C) E2 = $1\over2$E1

(D) E2 = $1\over4$E1

thumb_up_off_alt 3 like thumb_down_off_alt 0 dislike

1 Answer

more_vert
 
done_all
Best answer

Ans : (D) E2 = $1\over4$E1

thumb_up_off_alt 2 like thumb_down_off_alt 0 dislike
more_vert
Thanks for answer
Welcome to Jee Neet QnA, where you can ask questions and receive answers from other members of the community.

1.1k questions

771 answers

366 comments

77 users

...