Proton and electron are moving along circular path with same speed. Find out ratio of debroglie wavelength that is $\lambda_e\over\lambda_p$. If mp = 1836 me.
(1) 1836
(2) 1837
(3) $1\over1836$
(4) $1\over1837$
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Ans. (1) 1836
Sol. $\lambda={h\over mv}$
${\lambda_e\over\lambda_p}={m_p\over m_e}=1836$
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