Given f(0) = 1, f(2) = e2 also f'(x) = f'(2 – x), then the value of ∫02 f(x) dx is

Question

Given f(0) = 1, f(2) = e² also f'(x) = f'(2 – x), then the value of $\int\limits_0^2$ f(x)dx is

(1) 1 – e²

(2) 1 + e²

(3) e

(4) e²