Given f(0) = 1, f(2) = e2 also f'(x) = f'(2 – x), then the value of $\int\limits_0^2$ f(x)dx is
(1) 1 – e2
(2) 1 + e2
(3) e
(4) e2
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The integral $\int\limits_0^2{||x-1|-x|dx}$ is equal to : Numerical Value Type
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