Given f(0) = 1, f(2) = e^{2} also f'(x) = f'(2 – x), then the value of $\int\limits_0^2$ f(x)dx is

(1) 1 – e^{2}

(2) 1 + e^{2}

(3) e

(4) e^{2}

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The integral $\int\limits_0^2{||x-1|-x|dx}$ is equal to : Numerical Value Type

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