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As we know,
ΔG = ΔH - TΔS
For the reaction to be spontaneous:
ΔG = -ve
ΔG is negative at all temperature when:
ΔG(-ve) = ΔH(-ve) - T ΔS(+ve)
i.e., ΔH < 0 and ΔS > 0
Also, when ΔS = 0, ΔG = -ve
ΔG(-ve) = ΔH(-ve) -T(0)
Ans: (A) , (C)
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