The value of (–15C1 + 2.15C2 – 3.15C3 + ....... –15.15C15) + (14C1 + 14C3 + .......... + 14C11) is
(1) 216 – 14
(2) 213 – 14
(3) 213 – 13
(4) 214
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Find the value of n+1C2 + 2(2C2 + 3C2 + …… + nC2) = ? (1) $n(n+1)(2n-1)\over6$ (2) $n(n+1)(2n+1)\over6$ (3) $(n-1)n(n+1)\over6$ (4) $n(n+1)\over2$
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