There are two positive number p and q such that p + q = 2 and p^{4} + q^{4} = 272. Find the quadratic equation whose roots are p and q.

(1) x^{2} – 2x + 2 = 0

(2) x^{2} – 2x + 135 = 0

(3) x^{2} – 2x + 16 = 0

(4) x^{2} – 2x + 130 = 0

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Ans : (3) x^{2} - 2x + 16 = 0

Solution :

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