The total energy of an electron in the n^{th} stationary orbit of the hydrogen atom can be obtained by

(1) $E_n=-13.6×n^2$ eV

(2) $E_n={13.6\over n^2}$ eV

(3) $E_n=-{13.6\over n^2}$ eV

(4) $E_n=-{1.36\over n^2}$ eV

If you are commenting for the first time, please read the guidelines.

If you are answering for the first time, please read the guidelines.

Welcome to Jee Neet QnA, where you can ask questions and receive answers from other members of the community.

Join our Telegram group for live discussion.

Subscribe our YouTube channel for video solutions with explanation.

Download Jee Neet QnA Books in PDF for offline learning.

1.2k questions

842 answers

384 comments

92 users