The Gibbs energy change (in J) for the given reaction at [Cu2+] = [Sn2+] = 1 M and 298 K is :
Cu(s) + Sn2+(aq.) $\longrightarrow$ Cu2+ (aq.) + Sn(s);
($E_{Sn^{2+}|Sn}^0$ = –0.16 V, $E_{Cu^{2+}|Cu}^0$ = 0.34 V, Take F = 96500 C mol–1)
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