Question

In Carius method of estimation of halogen, 0.172 g of an organic compound showed presence of 0.08 g of bromine. Which of these is the correct structure of the compound ?

(1) H3C–Br

(2) H3C–CH2–Br

(3) 

(4) 

Comments

Some basic principles of organic chemistry, Quantitative analysis

Answer 1

Ans. (3) 

Sol. Mole of Bromine = $0.08\over80$ = 10^-3mole

Molar mass of compound = $0.172\over M$ = 10^-3

M = $0.172\over10^{-3}$ = 172 gm

Molar mass of  = 80 + 72 + 6 + 14 = 172 gm